Question: 1 4 . 1 0 : State Elimination Consider the DFA with two states and alphabet { a , b } , whose language is

14.10

: State Elimination

Consider the DFA with two states and alphabet

{

,

},

whose language is all strings with an odd number of b

.

Form an r

.

. -

NFA from this DFA and eliminate first the original start state, then the original final state. Then the resulting regular expression for this language is

(

*

) (

+

*

) * . (

We are allowed to simplify using the fact that

\

lambda is the identity for concatenation.

)

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