Question: ( 1 . 5 ) 0 1 2 1 ( 4 x 2 9 ) 1 2 d x , Using the substitution x =

(1.5)0121(4x29)12dx, Using the substitution x=32tanu
( 1 . 5 ) 0 1 2 1 ( 4 x 2 9 ) 1 2 d x , Using the

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