$1\mathrm{.}6\mathrm{.}6.$ Start with the logistic equation $($dx$)/($dt$)=$kx$($M$-$x$).$ Suppose we modify our harvesting. That is we

will only harvest an amount proportional to current population. In other words, we harvest hx per unit of

time for some h$>0$h replaced with hx kM$>$h$,$ then the equation is still logistic.

ckM $?$