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The average energy $E($in kcal$)$ needed for a lizard to walk or run a distance of $1$ km has been modeled by the equation

$E(m,v)=2\mathrm{.}65m^{0\mathrm{.}66}+\frac{3\mathrm{.}5m^{0\mathrm{.}75}}{v}$

where $m$ is the body mass of the lizard $($in grams$)$ and $v$ is its speed $($in $k\frac{m}{h}).$ Calculate $E_m(415,8)$ and $E_v(415,8)$ and interpret your answers.t

$E_m(415,8)=$ kca$\frac{l}{g}($rounded to one decimal place$),$ so the rate at which the energy a lizard needs is changing as its weight increases is

$q,$ kilocalories per gram when $m=g$ and $v=k\frac{m}{h}.$

$E_v(415,8)$~~ $q,)($rounded to one decimal place$),$ so the rate at which the energy a lizard needs is changing as its speed increase is $q,$ kcal of energy for each $1k\frac{m}{h}r$ increase in speed, when $m=g$ and $v=k\frac{m}{h}.$