$1\mathrm{.}7($Approximate $)$ can be computed using the following formula:

$=4(1-\frac{1}{3}+\frac{1}{5}-\frac{1}{7}+\frac{1}{9}-\frac{1}{11}+$dots$)$

Write a program that displays the result of $4(1-\frac{1}{3}+\frac{1}{5}-\frac{1}{7}+\frac{1}{9}-\frac{1}{11})$ and $4(1-\frac{1}{3}+\frac{1}{5}-\frac{1}{7}+\frac{1}{9}-\frac{1}{11}+\frac{1}{13}).$ Use $1\mathrm{.}0$ instead of $1$ in your program.