1. A projectile of mass m = 0.50 kg is launched with the angle 0 60...

 

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1. A projectile of mass m = 0.50 kg is launched with the angle 0 60 and vo=40.0 m/s. Here, we ignore air friction. (a) Calculate the initial mechanical energy E = KE + PE. PE E = 0 (b) What is the kinetic energy of the projectile when it reaches the maximum height h? v R (12) ( <5 60) = 20m/s intial velocity 40! 3/3 angle=60 m=0.5kg Speed at the top: v=1 KE= (c) What is the potential energy of the projectile when it reaches the maximum height h? (do not use hmax= sin20 to find hmax. Use the conservation of the total mechanical energy) Vy2vg2 = (-295) 20 PE= Vy=0 h max at max, height x = (usin 60120 29 (d) The maximum hmax= 1. A projectile of mass m = 0.50 kg is launched with the angle 0 60 and vo=40.0 m/s. Here, we ignore air friction. (a) Calculate the initial mechanical energy E = KE + PE. PE E = 0 (b) What is the kinetic energy of the projectile when it reaches the maximum height h? v R (12) ( <5 60) = 20m/s intial velocity 40! 3/3 angle=60 m=0.5kg Speed at the top: v=1 KE= (c) What is the potential energy of the projectile when it reaches the maximum height h? (do not use hmax= sin20 to find hmax. Use the conservation of the total mechanical energy) Vy2vg2 = (-295) 20 PE= Vy=0 h max at max, height x = (usin 60120 29 (d) The maximum hmax=