1 a2 + be a3 v) |1 b2 + ca b31 = -(a-b)(b-c)(c-a)(a2+b2+c? ) 1 c2 + ab C3 a2 bc ac + c2 vi)laz + ab b2 ac | = 4a2b2cz ab b2 + bc C2 - a2 ab ac vii) | ab - 62 bc | = 4a262c2 ac bc - C2 -a(b2 + c2 - a2) 2b3 viii) | 2a3 2c3 -b(c2 + a2 - 62) 2c3 2a3 263 c(a2 + 62 - ( 2 ) stoda = abc (b2 + c2 + a2)3 1 1 1 5 8. Determine the product [1 2 - 3] [ 9 -1 -4]and use it to solve the 2 3 5 -3 -1 system of equations. x+y+z=0, x+2y-3z=-14, 2x-y+3z=9 9. Using the properties of determinants, prove the following: 1+x 1 1 1 1 1ty 1 | = xyz + xy +yz +zx (CBSE-2009) 1 1 1+z 10. If x, y, z all are different & x x2 1+x3 ly y2 1 + y3| = 0, show that xyz = -1 z z2 1+ 23 1 1. If A & B are square matrices of order 3 such that |A| = -1 & |B|=3, then find the value of | 3ABI