1. Backspace String Compare Two strings are said to be the same if they are of the same length and have the same character at each index. Backspacing in a string removes the previous character in the string. Given two strings containing lowercase English letters and the character '#' which represents a backspace key, determine if the two final strings are equal. Return 1 if they are equal or 0 if they are not. Note that backspacing an empty string results in an empty string. Example s1 = 'axx#bb#c' s2 = 'axbd#c#c' In the first string, one 'x' and one 'b' are backspaced over. The first string becomes axbc. The second string also becomes axbc. The answer is 1. Function Description Complete the function compareStrings in the editor below. compareStrings has the following parameter(s): string s1: the first string string s2: the second string Returns int: either 0 or 1 Constraints • 1 ? length of s1 ? 2*105 • 1 ? length of s2 ? 2*105 • Both s1 and s2 contain lowercase English letters and/or the character '#' only. ? Input Format For Custom Testing 10 11 12 13 14 15 16 17 18 19 20 21 22 23 vif 24 25 26 27 28 29 30 31 32 33 34 35 # # Complete the 'compareStrings' function below. # # The function is expected to return an INTEGER. # The function accepts following parameters: # 1. STRING s1 # 2. STRING S2 # def compareStrings (s1, s2): # Write your code here __name__ == '__main__': fptr = open(os.environ['OUTPUT_PATH'], 'w') s1 = input() s2 = input() result = compareStrings (s1, s2) fptr.write(str(result) + '') fptr.close()r? Input Format For Custom Testing The first line contains a string, s1. The second line contains a string, s2. ? Sample Case 0 Sample Input For Custom Testing yf#c# yy#k#pp## Sample Output 1 Explanation Both the strings s1 and s2 result in "y" after processing backspaces. ? Sample Case 1 Sample Input For Custom Testing hacc#kk# hb##ackk## Sample Output 0 Explanation The first string becomes "hack" while the second string becomes "ac".