$1.$ Calculate the rate for each trial $(1-6)$ using Equation $(3).$

$2.$ Use the method of initial rates to find the order with respect to each reactant. For example, if we compare trial $1$ and trial $2,$ we double the concentration of H$2$C$2$O$4$ while keeping the concentration of KMnO$4$ constant in the two trials. So the ratio of the rates $($using Equation $2)$ are proportional to the concentrations of H$2$C$2$O$4$ only and we can find the order $($y$)$ with respect to H$2$C$2$O$4.$ Similarly, we can solve for $$x$$ by comparing trials $1$ and $5.$

$3.$ Once you have found the rate law for the reaction you can then calculate the rate constant for each trial $(1-6)$ by inserting the rate and the molar concentrations of each reactant in the rate law.