Question: 1. Considering the unbalanced equation below, if you weighed 0.62 1 point g of Li2CO3 for the reaction, how many moles of Li2CO3 would you

1. Considering the unbalanced equation below, if you weighed 0.62 1

1. Considering the unbalanced equation below, if you weighed 0.62 1 point g of Li2CO3 for the reaction, how many moles of Li2CO3 would you have? (assume the molar mass of Li2CO3 is 73.89 g/mol) LI2CO3 (s) + HCl (aq) -> LICI (aq) + H2O (1) + CO2 (g). 0.0084 mol 8 x 10-3 mol 8.4 x 10-3 0.00839 mol

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