1. Convert the following to km: a) 1600.0 m = b) 2050 cm = d) 23000...

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1. Convert the following to km: a) 1600.0 m = b) 2050 cm = d) 23000 μm = e) 0.4210 dag=_ f) 0.129 cm = g) 56450 CL = 2. Convert the following measurements. a) 10.034 mJ =_ b) 0.050 cm = c) 0.0325 kJ = a) 36 C= km b) -12 C= km K K cJ mm m _dg mm c) 1.030 hm = d) 2450 dm = hL 3. Convert the following temperatures. h) 36.45 CL = i) 1024 g = j) 1202 ml= k) 2.65 km = 1) 46890 μg = m) 268000 cm=_ n) 1.2 TPa =. c) 75 C = km d) 398 K = km μL kg L Another important conversion for chemistry is the conversion from the Celsius temperature scale to the Kelvin temperature scale. Since 0°C =273 K, add 273 to your Celsius temperature to convert to Kelvin. m mg km GPa e) 1.25 Mm = f) 0.034 Mm=_ o) 356 Mb= p) 450 nm = q) 3.5 nm = r) 0.076 pm =. s) 0.00023 MJ= t). 56.2 hm =. u) 0.56 dal = e) 450 K = f) 246 K= km km Gb μm pm um kJ Mm mL W1 1. Convert the following to km: a) 1600.0 m = b) 2050 cm = d) 23000 μm = e) 0.4210 dag=_ f) 0.129 cm = g) 56450 CL = 2. Convert the following measurements. a) 10.034 mJ =_ b) 0.050 cm = c) 0.0325 kJ = a) 36 C= km b) -12 C= km K K cJ mm m _dg mm c) 1.030 hm = d) 2450 dm = hL 3. Convert the following temperatures. h) 36.45 CL = i) 1024 g = j) 1202 ml= k) 2.65 km = 1) 46890 μg = m) 268000 cm=_ n) 1.2 TPa =. c) 75 C = km d) 398 K = km μL kg L Another important conversion for chemistry is the conversion from the Celsius temperature scale to the Kelvin temperature scale. Since 0°C =273 K, add 273 to your Celsius temperature to convert to Kelvin. m mg km GPa e) 1.25 Mm = f) 0.034 Mm=_ o) 356 Mb= p) 450 nm = q) 3.5 nm = r) 0.076 pm =. s) 0.00023 MJ= t). 56.2 hm =. u) 0.56 dal = e) 450 K = f) 246 K= km km Gb μm pm um kJ Mm mL W1

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Step1 Length relations 1 m 10 dm 100 cm 1000 mm 01 dam 001 hm 0001 km 1 km 10 hm 100 dam 1000 m 1000... View the full answer