= 1. Given the life table below, and a constant force of interest 7%, compute the following. (Note that Z means a present value random variable for a single insurance payout as appropriate to the notation, like in the lectures) a) A5 b) A1 5:41 c) A5:47(that is, 4Es)- d) 4/A5 e) Var(25) f) Var(Z) Ix 04 100,000 14 98,000 24 95,000 34 90,000 4 83,000 52 75,000 64 65,000 74 55,000 8 44,000 9 36,000 104 23,000 11 10,000 12 04 = 1. Given the life table below, and a constant force of interest 7%, compute the following. (Note that Z means a present value random variable for a single insurance payout as appropriate to the notation, like in the lectures) a) A5 b) A1 5:41 c) A5:47(that is, 4Es)- d) 4/A5 e) Var(25) f) Var(Z) Ix 04 100,000 14 98,000 24 95,000 34 90,000 4 83,000 52 75,000 64 65,000 74 55,000 8 44,000 9 36,000 104 23,000 11 10,000 12 04