Question: 1. If cot 2A = tan 3A, find the value of A in degreesa. 24 degrees b. None of these C. 12 degrees d. 6

















![that the Caucasian [he or she] is either A or AB. a.](https://s3.amazonaws.com/si.experts.images/answers/2024/06/66655449bca97_74566655449ad8ea.jpg)


1.




















If cot 2A = tan 3A, find the value of A in degreesa. 24 degrees b. None of these C. 12 degrees d. 6 degrees e. 18 degreesFor the equation whose general solution is y = Cx2 +1a. xy' = 2(1-y) b. None of these C. xy' = 2(y-1) d. y' = 2(x-1) e. x' = 2(y-1)Find the distance from the intersection of the lines to the origin. a. 2.828 b. None of these C. 1.828 d. 8.828 e. 6.828\fLinearity Property Change of Scale Property Second Shifting Property First Shifting Property None of these Solve the particular solution of dy/dx-3y/x = x^3 if y(1) = 4.a. y =3x2 + x + 8 b. y = 3x2 + 4x + 2 C. y = X4 + 3x3 d. y = x4 e. None of theseIn the expression ), the letter n represents\fFind the convolution between cos(t) and sin(t)2 a. (1/2) t sin t b. (1/2) t sin t 2 C. (1/2) t cost d. (1/2) t cost e. None of these'American was tested by their blood samples. A. B, AB, and 0. The preporticnt of the blood type samples of the Caucasians are 0.41. 0.1. 0.04. and 0.45. _ respectively. Find the probability that the Caucasian [he or she] is either A or AB. a. 0.55 b. 0.43 C. None of these d. 0.45 e. 0.52Solve the differential equation dy - xdx = 0 if the curve passes through (1, 0).a. None of these b. 2x^2 + 2y - 2 = 0 c. X^2 - 2y - 1 = 0 d. 3x^2 + 2y - 3 = 0 e. 2y +x42 - 1 = 02 2 Determine the equation of the line normal to the graph x +3xy +y =5 at the point (1, 1)a. Xty = 1 b. None of these C. X+y=0 d. x-y = 1 e. X-y=0
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
