Question: 1. If cot 2A = tan 3A, find the value of A in degreesa. 24 degrees b. None of these C. 12 degrees d. 6

 1. If cot 2A = tan 3A, find the value ofA in degreesa. 24 degrees b. None of these C. 12 degreesd. 6 degrees e. 18 degreesFor the equation whose general solution isy = Cx2 +1a. xy' = 2(1-y) b. None of these C.xy' = 2(y-1) d. y' = 2(x-1) e. x' = 2(y-1)Find thedistance from the intersection of the lines to the origin. a. 2.828b. None of these C. 1.828 d. 8.828 e. 6.828\fLinearity Property Changeof Scale Property Second Shifting Property First Shifting Property None of theseSolve the particular solution of dy/dx-3y/x = x^3 if y(1) = 4.a.y =3x2 + x + 8 b. y = 3x2 + 4x+ 2 C. y = X4 + 3x3 d. y = x4e. None of theseIn the expression ), the letter n represents\fFind theconvolution between cos(t) and sin(t)2 a. (1/2) t sin t b. (1/2)t sin t 2 C. (1/2) t cost d. (1/2) t coste. None of these'American was tested by their blood samples. A. B,AB, and 0. The preporticnt of the blood type samples of theCaucasians are 0.41. 0.1. 0.04. and 0.45. _ respectively. Find the probabilitythat the Caucasian [he or she] is either A or AB. a.0.55 b. 0.43 C. None of these d. 0.45 e. 0.52Solve thedifferential equation dy - xdx = 0 if the curve passes through

1.

(1, 0).a. None of these b. 2x^2 + 2y - 2 =0 c. X^2 - 2y - 1 = 0 d. 3x^2 +2y - 3 = 0 e. 2y +x42 - 1 = 022 Determine the equation of the line normal to the graph x+3xy +y =5 at the point (1, 1)a. Xty = 1 b.None of these C. X+y=0 d. x-y = 1 e. X-y=0image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed

If cot 2A = tan 3A, find the value of A in degreesa. 24 degrees b. None of these C. 12 degrees d. 6 degrees e. 18 degreesFor the equation whose general solution is y = Cx2 +1a. xy' = 2(1-y) b. None of these C. xy' = 2(y-1) d. y' = 2(x-1) e. x' = 2(y-1)Find the distance from the intersection of the lines to the origin. a. 2.828 b. None of these C. 1.828 d. 8.828 e. 6.828\fLinearity Property Change of Scale Property Second Shifting Property First Shifting Property None of these Solve the particular solution of dy/dx-3y/x = x^3 if y(1) = 4.a. y =3x2 + x + 8 b. y = 3x2 + 4x + 2 C. y = X4 + 3x3 d. y = x4 e. None of theseIn the expression ), the letter n represents\fFind the convolution between cos(t) and sin(t)2 a. (1/2) t sin t b. (1/2) t sin t 2 C. (1/2) t cost d. (1/2) t cost e. None of these'American was tested by their blood samples. A. B, AB, and 0. The preporticnt of the blood type samples of the Caucasians are 0.41. 0.1. 0.04. and 0.45. _ respectively. Find the probability that the Caucasian [he or she] is either A or AB. a. 0.55 b. 0.43 C. None of these d. 0.45 e. 0.52Solve the differential equation dy - xdx = 0 if the curve passes through (1, 0).a. None of these b. 2x^2 + 2y - 2 = 0 c. X^2 - 2y - 1 = 0 d. 3x^2 + 2y - 3 = 0 e. 2y +x42 - 1 = 02 2 Determine the equation of the line normal to the graph x +3xy +y =5 at the point (1, 1)a. Xty = 1 b. None of these C. X+y=0 d. x-y = 1 e. X-y=0

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