1) If CS=3499H and IP =2500H, find: (a) The logical address (b) The physical address (c)...

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1) If CS=3499H and IP =2500H, find: (a) The logical address (b) The physical address (c) The lower and upper ranges of the code segment. 2) If DS 3499H and the offset=3FB9H, find: (a) The logical address (b) The physical address (c) The lower and upper ranges of the code segment. 3) Assume that the physical address for location is 0046CH. Suggest a possible logical address. 4) If an instruction that needs to be fetched is in physical memory location 389F2H and CS=2700H, does the code segment range include it or not? If not, what value should be assigned to CS if the IP must be =1282H? 1) If CS=3499H and IP =2500H, find: (a) The logical address (b) The physical address (c) The lower and upper ranges of the code segment. 2) If DS 3499H and the offset=3FB9H, find: (a) The logical address (b) The physical address (c) The lower and upper ranges of the code segment. 3) Assume that the physical address for location is 0046CH. Suggest a possible logical address. 4) If an instruction that needs to be fetched is in physical memory location 389F2H and CS=2700H, does the code segment range include it or not? If not, what value should be assigned to CS if the IP must be =1282H?

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To address these questions well need to understand how memory segmentation works in a typical x86 architecture In x86 systems memory is organized into ... View the full answer