1. In a man-machine manufacturing cycle, the worker does part of their work while the machine is running (5.27 min) and the rest after the machine has finished (0.65 min). The machine takes 5.62 min to complete its cycle. The PFD allowance factor for the worker is 12%. The allowance factor for the machine is 25%. Determine the standard time for the cycle. Enter the units as "min".

2. For the previous problem, determine the expected daily output based on the standard time. Enter the units as "pc". Note that this number can include partial units as it is an average of all workers.

3. Given the information in the previous problems, determine the worker's efficiency for the shift on a day when they produced 72 pc. On that day, the worker lost 39 minutes due to delays, rest breaks, and personal time. Note: while this is called worker efficiency, the worker does not control much of the day because the machine could have delays, breakdowns, etc. Enter your answer with the units "%".

4. Using the data from the previous questions, including the specific data for the single day, determine the worker's performance on the operator's controlled portion (external) of the shift. Assume the operator's performance on the internal part of the machine cycle is good enough to finish before the machine. Remember that performance only considers the time when the operator is in control and actually working. Enter the units as "%".