Question: 1 . Lead compensator: Consider a second - order plant model given by ( G ( s ) = frac { 4 0

1. Lead compensator: Consider a second-order plant model given by \( G(s)=\frac{40}{s(s+2)}\).
Figure 1: Cascade compensation.
For a closed-loop system as in Figure 1, we desire overshoot to be approximately \(26\%\) for a step input and the settling time (with a \(2\%\) criterion) of the system to be about 800 ms . Design a phase-lead compensator \( G_{c}(s)=\frac{K(s+z)}{(s+p)}\) using the root locus method.
(a) Determine the desired dominant conjugate pair of poles.
(b) Use Matlab to view the root locus of the uncompensated system; does the root locus come close to the desired pole locations?
(c) Select a zero location \( s=-z \) informed by the desired pole location. Use the angles of loop gain poles and zero to the desired pole location to determine compensator pole location \( s=-p \).(A sketch of the loop gain poles and zeros will help you with the trigonometry of the angles; note that in Matlab atand and tand operate in units of degrees.)
(d) Determine the gain \( K \)(again, a sketch of the loop gain poles and zeros will help you apply Pythagorus's formula).
(e) Plot the root locus for your design, e.g., rlocus (GcG)
(f) Report the closed-loop pole locations.
(g) Use Matlab to determine the step response characteristics, e.g., stepinfo(feedback(GcG,1))
(h) How do your P.O. and \( T_{s}\) compare to the desired values? If they differ, comment briefly why.
(i) For your design, determine the error constant, \( K_{v}\), for a ramp input.
1 . Lead compensator: Consider a second - order

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