Question: ( 1 ) n = 0 ( - 1 ) n x 2 n ( 2 n ) ! . ( 2 ) n =

(1)n=0(-1)nx2n(2n)!.(2)n=0(-1)nx2n(2n)!f''(x)+f(x)=0.
 (1)n=0(-1)nx2n(2n)!.(2)n=0(-1)nx2n(2n)!f''(x)+f(x)=0.

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