1. Observe the single-cycle implementation of the MIPS processor discussed in class. For each instruction in the following code sequence, give the: (1) Upper input to the ALU. (2) Lower input to the ALU. (3) Result of the ALU (4) ZERO output of the ALU (5) Value getting written to the register file. (6) Value going into the PC Assume that St1 contains the decimal value 8, St3 contains the decimal value 112, and that the memory location 8 bytes below Stl contains the decimal value 24. If the value isn't set or we don't care, write "X". If the value going to the PC is the current value of the PC+4, it's fine to just write "PC+4." ALU upper ALU lower ALU result ALU Value written Value going to register file into the PC ZERO Loop: lw St0, 8(St1) add St1, St0, St0 addi St2, St1, 64 bea St2, St3, loop