Question: (1 point) A first order linear equation in the form y + p(z)y = f (I) can be solved by finding an integrating factor u(x)

(1 point) A first order linear equation in the
(1 point) A first order linear equation in the form y + p(z)y = f (I) can be solved by finding an integrating factor u(x) = exp( / p(x) dx) (1) Given the equation y' sin() + ycos(x) = > sin (x) find (3) = (2) Then find an explicit general solution with arbitrary constant C. (3) Then solve the initial value problem with y(x/2) = 3

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