Question: (1 point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = and f (x) =
(1 point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = and f" (x) = Let a = 3/2. Then '(3/2) = and f" (3/2) = = Q(x), the quadratic approximation to cos(x) at a = 3/2 is: Q(x) == Use Q(x) to approximate cos(4.6). cos(4.6)
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