$(1$ point$)$ Do this part by hand and type the answer:

Put your $8-$digit birthdate $04\mathrm{.}29\mathrm{.}1998$ together in a vector of size$\_$t followed by your $10-$digit $650\mathrm{.}587\mathrm{.}8484$ mobile number together in an array or vector: You can use fake numbers if you worry about personal information but do not use the numbers in the example I give here.

A $=\{$mm$.$dd$.$yyyy$.$xxx$.$xxx$.$xxxx$\}=\{$mmddyyyyxxxxxxxxxx$\}$

Example: $12\mathrm{.}13\mathrm{.}2003\mathrm{.}415\mathrm{.}723\mathrm{.}2300=121320034157232300$

Add the digits $1$ through $9$ After the first nine digits and after the second nine digits. So$,$ declare a vecotr A or array size$\_$t A$[]$ of $182-$digit numbers:

Example:

$12-13-2003-415-723-2300$ becomes:

vector A $=\{11,22,13,34,25,06,07,38,49,$

$11,52,73,24,35,26,37,08,09\}$

Use your own numbers, not the given example ones.

I will not accept the numbers given in this example. Remove the zero from the numbers starting with a zero: Answer:

vector A $=\{11,22,13,34,25,06,07,38,49,$

$11,52,73,24,35,26,37,8,9\}$

You can use the vector A as an array when indexing A$[0]=11,$ etc. A$.$size$()$ is the size.

Use this resulting answer of yours in all the questions asking you to use $($A$).$ Insert the elements of A in hash table H of size $10.$ H is a vector of int is size $10.$

Use chaining in case of more than one value.

Draw the table or list the values.

The hash function is the sum of the number $10.$; f$($n$)=$ n$\%10$; initial values are $-1.$