(1 point) For this LP z = -2x1 x2 + x3 < 3 max s.t. X1 + x2 + X3 X2 + x3 > 2 X1 + x3 = 1 X1, X2, X3 2 0 Rowo of the optimal Primal tableau is: X1 X2 X3 S1 e2 a2 az rhs 1 4 1 1 +2 (1) Read y = [y y2 y3] = CBy B- from the optimal tableau and knowing that y is dual optimal and that y b = = , the value of is (2) The current optimal basis BV is {S1, X2, x3}. Does it remain optimal if c1 is changed to 6? (y/n) 1 (3) Suppose instead we consider Change 4 where c1 = 2 and a = 1 Does the current dual optimal solution remain feasible? (y/n) (4) What is the possibly new optimal value of after this change is made? VI AI I