(1 point) Given that the acceleration vector isa(t)=(-4cos(-2t))i+(-4sin(-2t))j+(-3t)k, the initial velocity isv(0)=i+k, and the initialposition vector isr(0)=i+j+k, compute:A. The velocity vector v(t)=i+j+kB. The position vector r(t)=i+j+t-t32+1kNote: the coefficients in your answers must be entered in the form of expressions in the variable t; e.g."5cos(2t)