$(1$ point$)$ Let $f(x)=\frac{8}{5-8x}.$

Then the slope of the tangent line to the graph of $y=f(x)$ at the point $(,-\frac{8}{3})$

is the limit as $x$ tends to of the following expression

$\frac{(\frac{8}{5-8x})-(\frac{8}{-3})}{x-}$

The value of this limit is

$$

It follows that the equation of the tangent line is $y=$