Question: (1 point) Let's prove that K12 is not planar: First, how many vertices and how many edges does K12 have? U = 12 and e

(1 point) Let's prove that K12 is not planar: First, how many vertices and how many edges does K12 have? U = 12 and e = If we assume that K12 were planar, then how many faces would it have? f = However, since every face is bounded by at least edges, and every edge borders exactly faces, we can get a bound on the number of faces. What is the largest number of faces possible based on this line of reasoning? f5 This is a contradiction, so K12 is not planar. QED

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