$(1$ point$)$ Suppose $h(x)=\sqrt[\phantom{2}]{f(x)}$ and the equation of the tangent line to $f(x)$ at $x=1$ is

$y=4+2(x-1)$

Find $h^{\text{'}}(1).$

$h^{\text{'}}(1)=$

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The answer above is NOT correct.

$(1$ point$)$ Suppose $h(x)=\sqrt[\phantom{2}]{f(x)}$ and the equation of the tangent line to $f(x)$ at $x=1$ is

$y=4+2(x-1)$

Find $h^{\text{'}}(1).$

$h^{\text{'}}(1)=$

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