$(1$ point$)$ The differential equation

$y+4y^5=(y^7+4x)y^{\text{'}}$

can $be$ written $in$ differential form:

$M(x,y)dx+N(x,y)dy=0$

where

$M(x,y)=$

The term $M(x,y)dx+N(x,y)dy$ becomes $an$ exact differential $if$ the left hand side above $is$ divided $by{y}^5.$ Integrating that new equation, the solution $of$ the differential equation $is$

$=C.$