Question: (1 point) The general equation for a circle is a(x2 + y ) + bx + cy+ d= 0. There is exactly one circle passing

(1 point) The general equation for a circle is
(1 point) The general equation for a circle is a(x2 + y ) + bx + cy+ d= 0. There is exactly one circle passing through the points (-3, 2), (-2, 3), and (0, 0). Find an equation for this circle. ( x 2 + 12 ) + x + y + = 0

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