Question: (1 point) Use linear approximation, i.e. the tangent line, to apprmttmate 2.872 as follows: Let f (x) = x2. The equation of the tangent line

 (1 point) Use linear approximation, i.e. the tangent line, to apprmttmate

2.872 as follows: Let f (x) = x2. The equation of the

(1 point) Use linear approximation, i.e. the tangent line, to apprmttmate 2.872 as follows: Let f (x) = x2. The equation of the tangent line to x) at x = 3 can be written in the form J; = mx + b where: m = and b: Using thisI we find our approximation for 2.3?2 is ('I point) Use linear approximation to approximate 1/492 as follows. Let f (x) = . The equation of the tangent line to x) at x = 49 can be written in the form y = mx + 1:. Compute m and b. Using this find the approximation for V492

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