Question: 1 / / pre: ( a > 1 ) ( M > = 0 ) ( k > = 1 ) 2 int mySum (

1// pre: (a >1)(M >=0)(k >=1)
2 int mySum(int k)
3 if (k ==1)
4 return M
5 else
6 return mySum(k-1)+ M*pow2(a, k-1)
7// post: returns M*(a2k -1)/(a*a -1)

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