1. Results F = 11.2 kN/2= 5.60 kN or 5600 N on each rod Area = A=TD/4...

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Results F = 11.2 kN/2= 5.60 kN or 5600 N on each rod Area = A=TD/4 = T(12.0 mm)2/4 = 113 mm o=F/A = 5600 N/113 mm = 49.5 N/mm = 49.5 MPa Let's solve the above problem with a different load and rod diameter combination as given below; Cases Load (kN) Rod Diameter (mm) 1 10 2 12 3 12 What is the stress in the rods based on these new parameters? 1 1 point Problem parameters for Case #1: Cases Note: 10 15 18 1 Load (kN) What is the Normal Stress in MPa on the rod? 10 Rod Diameter (mm) 10 Give your answer rounded to 1 decimal place i.e. 43.45223 = 43.5 or 43.44223 = 43.4 Do NOT include any units or other text. The size of your numeric value should be given in Mega Pascals (MPa). i.e. if your answer is "43,000,000" Pascals (Pa) then enter this as "43.0" (Do NOT enter "43.0 MPa") tou Results F = 11.2 kN/2= 5.60 kN or 5600 N on each rod Area = A=TD/4 = T(12.0 mm)2/4 = 113 mm o=F/A = 5600 N/113 mm = 49.5 N/mm = 49.5 MPa Let's solve the above problem with a different load and rod diameter combination as given below; Cases Load (kN) Rod Diameter (mm) 1 10 2 12 3 12 What is the stress in the rods based on these new parameters? 1 1 point Problem parameters for Case #1: Cases Note: 10 15 18 1 Load (kN) What is the Normal Stress in MPa on the rod? 10 Rod Diameter (mm) 10 Give your answer rounded to 1 decimal place i.e. 43.45223 = 43.5 or 43.44223 = 43.4 Do NOT include any units or other text. The size of your numeric value should be given in Mega Pascals (MPa). i.e. if your answer is "43,000,000" Pascals (Pa) then enter this as "43.0" (Do NOT enter "43.0 MPa") tou