Question: 1. The angular position of a point on a rotating wheel is given by: 0 = 19.77 + 5 t - 2.0t2 + 9 to

1. The angular position of a point on a rotating wheel is given by: 0 = 19.77 + 5 t - 2.0t2 +

many revolutions did the wheel make at t = 3.0 s? Note

The angular position of a point on a rotating wheel is given by: 0 = 19.77 + 5 t - 2.0t2 + 9 to where 0 is in radians and t in seconds. How many revolutions did the wheel make at t = 3.0 s? Note that 1.0 revolution = 27 radians. Please round your answer to one decimal place.A wheel has a constant negative angular acceleration (deceleration) of - 3.2 rad/s2. At the end of time interval t = 4.4 s, the wheel is found to be moving at 52 rad/s. What was the initial angular speed of the wheel? Please round your answer to one decimal place.A uniform disk, with mass M= 8.0 kg and radius 0.50 m, is mounted on a fixed horizontal axle as shown below. A block with a mass m = 2.0 kg hangs from a massless cord that is wrapped around the rim of the disk. The block is released from rest. What are the acceleration of the falling block and the tension in the cord. M T m

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