Question: The angular position of a point on a rotating wheel is given by 0 = 5.82 +3.00t2 + 1.66t3, where is in radians and t

The angular position of a point on a rotating wheel is given by 0 = 5.82 +3.00t2 + 1.66t3, where is in radians and t is in seconds. At t = 0, what are (a) the point's angular position and (b) its angular velocity? (c) What is its angular velocity at t = 4.62 s? (d) Calculate its angular acceleration at t = 2.88 s. (e) Is its angular acceleration constant?

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