Question: 1. The quadmtit: function x] = ab: 102 + k is in standard farm. (a) The graph of fis a parabola with vertex (x, y}

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1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in1. The quadmtit: function x] = ab: 102 + k is in
The quadmtit: function x] = ab: 102 + k is in standard farm. (a) The graph of fis a parabola with vertex (x, y} = ( |:| ] [b] It a > u, the graph offopens . In this case n} = k is the value uf n this case Em} = k is the value of f. [:1 If a

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