1 This problem involves some additional calculations involving PACCAR Hall. Consider again the W2455 beam examined in Lab 3 (i.e., beam B.8/11-B.8/13). a. In lab we determined that the equivalent uniform D + L load corresponding to the 38 k reactions for this beam would be 1.73 k/ft. Use the dead and live floor load values from the floor load map to calculate the dead load portion of this 1.73 k/ft loading (i.e., D/(D + L)). Don't forget to subtract the member's self weight first, then add it back in later once you've done a proportional split on the dead and live floor loads. b. Use this uniform dead load, wD , to determine the maximum displacement at the center of this beam due to dead load only, again assuming the connections act like simple supports. c. In a simple sense, camber can be used to accommodate dead loads so that floors are close to flat prior to live loading. Compare your dead load displacement to the specified camber of this beam. It won't match particularly well in this case, so see if you can identify some reasons why this might be so. d. The 38 kip end reactions