1. Translate the following code into MIPS code.

A[i - 6] = A[i + 2] + 10;

i = i + 7; A[3] = A[i - 1];

a) Assume A is an array of integers (each integer takes 4 bytes). A's address is stored at register $10. Also assume that the compiler associates the variable i to the register $11. b) Assume A is an array of characters (each character takes one byte). A's address is stored at register $10. Also assume that the compiler associates the variable i to the register $11.

2. Translate the following code into MIPS code.

j=0;

k=0;

for (i = 1 ; i < 50 ; i = i + 2)

{

K=k+1;

j = (i + j);

B[k] = j;

}

Assume the compiler associates the variables i, j, and k to the registers $t0, $t1, and $t2 respectively. Also, assume B is an array of integers and its address is stored at register $s1.

3. Translate the following code into MIPS code.

for (i=0; i<=5; i=i+1)

{

if (i != k)

k=(k *2)-1;

else

k=(k *4)+1;

}

Assume the compiler associates the variables i and k to the registers $s0 and $s1, respectively.