Translate the following code into MIPS code.

A[i - 6] = A[i + 2] + 10;

i = i + 7; A[3] = A[i - 1];

a) Assume A is an array of integers (each integer takes 4 bytes). A's address is stored at register $10. Also assume that the compiler associates the variable i to the register $11.

b) Assume A is an array of characters (each character takes one byte). A's address is stored at register $10. Also assume that the compiler associates the variable i to the register $11.

Please show me every step of how to solve it but not just answers. thank you!