Question: 1. Twelve orange pulp silage samples were divided at random into four groups of three. One group was left as an untreated control while the

 1. Twelve orange pulp silage samples were divided at random into

1. Twelve orange pulp silage samples were divided at random into four groups of three. One group was left as an untreated control while the other three groups were treated with formic acid, beet pulp, and sodium chloride, respectively. The observed moisture content of the silage samples are shown below. Sodium chloride Formic acid Beet pulp Control 80.5 89.1 77.8 76.7 79.3 75.7 79.5 77.2 79.0 81.2 77.0 78.6 (a) Obtain an analysis of variance table for the data and test the null hypothesis that all four treatments yield the same true average moisture content. Use a = 0.05

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