1. Use the standard deviation (normal curve) method of grading (1.5s and above = A, .5-1.5s = B, (-.5)-.5s = C, (-1.5)-(-.5)s = D, (-1.5)s and below = F) to determine the grading scale andthe number of students receiving each designated grade.Round themean and standard deviation to the nearest whole number.The raw test scores are as follows: 51, 65, 77, 48, 74, 58, 68, 78, 62,77, 52, 62, 68, 65, 75, 91, 88, 84, 66, 79.

Mean = _______

Standard Deviation = _______

Grading Scale# ofStudents Receiving Grade

A = ______ to____________

B = ______ to____________

C = ______ to____________

D = ______ to____________

F = ______ to____________

2. Use the following vertical jump scores to develop a five categoryevaluation scale (Excellent = .88s and above, Good = .28 - .87s, Average = (-.23)-.27s, Fair = (-.81)-(-.24)s, Poor = (-.82) and below).Calculate the scores for each category (round to thenearest tenth) and the number of subjects that scored within eachcategory.Round the mean and standard deviation to the nearest tenth.The vertical jump scores are as follows: 21, 29, 27.5, 26,29, 25, 33, 22, 27, 24, 27.5, 32.5, 26, 24, 22.5, 29.5, 22.5, 28, 25,35, 31.5, 27.5, 25.5, 22.5, 28.5, 27.

Mean = _______

Standard Deviation = _______

Category# of Subjects

Excellent = ______ to____________

Good= ______ to____________

Average= ______ to____________

Fair= ______ to____________

Poor= ______ to____________