1) When an object is thrown upward with an initial velocity of 80 ?ft/sec from a height of 576 ?ft, its height h after t seconds is given by the function below.

h(t)=-16t²+80t+576

what is the height of the object after 0 sec, 1 sec, 3 sec, 4 sec and 6 sec?

the height of the object is _____ ft

find the equivalent expression for the height h(t) by factoring

an equivalent expression is h(t) =

2)

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