1.

Write the equation in logarithmic farm. Assume that all constants are positive and not equal to 1. Ell-=1; (a) Use the sliders and set I = 1 and E = .5 1What is the largest value that works for 5? :l (Hint: check the box that says "Does it work' and use your arrow keys to move the slider one one-hundredth at a time] [b] Use the sliders and set 2: = .5 and set E = .3 The largest value that works for 5 is :5 = .22. {Notice as you make 5 P .22 , the values of the function are red, and when the values of 5 E .22 the values of the function are green} "filthyr doesn't it work when 5 I? .22? O 1when evaluating the function using values of 3:: outside the interval [ .22, .22], the value of the function doesn't lie within epsilon of .5] 0 When evaluating the function using values of 3: outside the interval [ .72, .23], the value of the function doesn't lie within epsilon of .5) O 1when evaluating the function using values of 3:: outside the interval [ .5, .5], the value of the function doesn't lie within epsilon of .5] Interact with the graph in order to determine a 5 so that if I: {1| 6: 5 , then lffz} LI as: E . Please 2 make sure 1your response is accurate to within three decimal places. Let HI] = 3:3, and let x > 1, and suppose that E = .1301. Determine 5 so that if I3 till i 5 , then Iz} LI s: E Use the fourstep definition of the derivative to find f'g] if x] = 4:2 + 53: + '5. Evaluate (f . 9) (x) f(x) = 3x - 5 g(x) = 2x - 4 (f - g) (x)