A JFET transistor with a resistor RS creates a constant current source in the figure above....
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A JFET transistor with a resistor RS creates a constant current source in the figure above. The value of the resistance R₁=1400 so that lo is 4 mA. Both Rc=27500 so that Ve is about 6.5V. Two BC546B BJT transistors form the differential amplifier. The supply voltage is ± 12 V. a) Let the input Vi1 on transistor Q1 get the signal voltage: Vil = 0,05- cos (2T-10³. t) V The input Vi2 on to transistor Q2 is just connected to ground and = OV. Calculate differential gain for the differential amplifier. b) Now set both inputs Vi1 on Q1 and Vi2 on Q2 to be Vil = V₁2 = 1,0-cos (2T-10³. t) V Calculate differential gain for the differential amplifier. Vil Rc Vol Q3 VE +12 V Vo2 |1Q Rs -12 V Rc Q₂ A JFET transistor with a resistor RS creates a constant current source in the figure above. The value of the resistance R₁=1400 so that lo is 4 mA. Both Rc=27500 so that Ve is about 6.5V. Two BC546B BJT transistors form the differential amplifier. The supply voltage is ± 12 V. a) Let the input Vi1 on transistor Q1 get the signal voltage: Vil = 0,05- cos (2T-10³. t) V The input Vi2 on to transistor Q2 is just connected to ground and = OV. Calculate differential gain for the differential amplifier. b) Now set both inputs Vi1 on Q1 and Vi2 on Q2 to be Vil = V₁2 = 1,0-cos (2T-10³. t) V Calculate differential gain for the differential amplifier. Vil Rc Vol Q3 VE +12 V Vo2 |1Q Rs -12 V Rc Q₂
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Answer A In option A the input V1 on transistor Q1 is set to the signal voltage Vil 005 cos 2 10 t V ... View the full answer
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