136 students at a college were asked whether they had completed their required English 101 course,...
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136 students at a college were asked whether they had completed their required English 101 course, and 82 students said "yes". Construct the 99% confidence interval for the proportion of students at the college who have completed their required English 101 course. Enter your answers as decimals (not percents) accurate to three decimal places. The Confidence Interval is ( Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 130 with 101 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. C.I. = 136 students at a college were asked whether they had completed their required English 101 course, and 82 students said "yes". Construct the 99% confidence interval for the proportion of students at the college who have completed their required English 101 course. Enter your answers as decimals (not percents) accurate to three decimal places. The Confidence Interval is ( Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 130 with 101 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. C.I. =
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To construct a confidence interval for proportion we can use the formula Confidence Interval p Z sqr... View the full answer
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