(14%) Problem 6: An arrow is shot from a height of 1.95 m toward a cliff of height H. It is shot with a velocity of 29 m/s at an angle of 60 above the horizontal. It lands on the top edge of the cliff 3.91 s later. * 33% Part (a) What is the height H of the cliff in m? H = 30.6 -| Grade Summary Deductions 0% Potential 100% sin() cos() tan() IT ( ) 7 8 9 HOME cotan() asin() acos() E 4 Submissions Attempts remaining: 991 atan() acotan() sinh() 1 2 3 0% per attempt) cosh() tanh() cotanh() 0 END detailed view o Degrees . Radians VO BACKSPA DEL CLEAR 1 0% 0% Submit Hint Feedback I give up! W N 0% Hints: 4 for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. -What direction is the acceleration in this problem? -What are the initial and final conditions of the motion? Which kinematic equation can you use to find the unknown variable? Draw the picture. Take the origin of x-y system at the ground. Mark initial position of arrow. Draw vectors of velocity and acceleration. Carefully check the signs of all components. * 33% Part (b) What is the maximum height reached by the arrow along its trajectory in meters? hmax = 24.70 * Attempts Remain 4 33% Part (c) What is the arrow's speed just before hitting the cliff in m/s