#18t

Test: Week 3...

Test: Week Question 18 of 20 This test: 100 point(s) possible This question: 5 point(s) possible Submit test In a survey of 1449 people, 1033 people said they voted in a recent presidential election. Voting records show that 69% of eligible voters actually did vote. Given that 69% of eligible voters actually did vote, (a) find the probability that among 1449 randomly selected voters, at least 1033 actually did vote. (b) What do the results from part (a) suggest? (a) P(X21033) = (Round to four decimal places as needed.) (b) What does the result from part (a) suggest? People are being honest because the probability of P(x 1033) is less than 5%. Some people are being less than honest because P(x2 1033) is less than 5%. Some people are being less than honest because P(x21033) is at least 1%. People are being honest because the probability of P(x21033) is at least 1%.