1.A C# Program Performs Celsius to Fahrenheit Transformation.

2.A structure costing Rs.700000.00 has been developed on a freehold land estimating 100 sq m as of late in a major city. Winning pace of land in the area is Rs.150.00 per sq m. Decide the net lease of the property, if the consumption on an active including sinking store is Rs.24000.00 per annum. Work out additionally the gross lease of the property each month.

3.An old structure has been bought by an individual at an expense of Rs.30000/ - barring the expense of the land. Compute the measure of yearly sinking store at 4% premium expecting the future lie of the structure as 20 years and the piece estimation of the structure as 10% of the expense of procurement.

4.A siphoning set with an engine has been introduced in a structure at an expense of Rs.2500.00. Accepting the existence of the siphon as 15 years, work out the measure of yearly portion of sinking store needed to be kept to aggregate the entire measure of 4% self multiplying dividends.

5.What is the promoted estimation of a property getting a net yearly lease of Rs.1000 and the most elevated pace of revenue common being 5%, pace of revenue is 8%?

6._____________ is the strategy of assessing or deciding the reasonable cost or estimation of a property like a structure, a plant, other designing constructions of different kinds.

7.A property brings a net yearly pay of Rs.900 deducting all outgoings. Exercise the promoted estimation of the property if the pace of revenue is 6% per annum.

8.Find the plinth region needed for the private convenience for an associate specialist in the compensation size of Rs.400.00 to 1000.00 each month.

9.Find the condition of the crossing point of the surface z=4-y2 with the x-y plane.

10.What is the articulation utilized for populace guaging by the arithmetical increment technique?

11.What is the articulation utilized for populace anticipating by the mathematical increment strategy?

12.Which strategy for populace conjecture consolidates both arithmetical increment and mathematical increment technique?

13.What will be the general populace of molecules in a ruby layer that creates a light emission 6943 at 300 K.

Answers;

1./*

2.* C# Program to Perform Celsius to Fahrenheit Transformation

3.*/

4.using Framework;

5.using System.Collections.Generic;

6.using System.Linq;

7.using System.Text;

8.

9.namespace program

10.{

11.class Program

12.{

13.static void Main(string[] args)

14.{

15.int celsius, faren;

16.Console.WriteLine("Enter the Temperature in Celsius(C) : ");

17.celsius = int.Parse(Console.ReadLine());

18.faren = (celsius * 9)/5 + 32;

19.Console.WriteLine("0Temperature in Fahrenheit is(F) : " + faren);

20.Console.ReadLine();

21.

22.}

23.}

24.}

25.

26.

Cost of development = Rs.700000.00

Cost of land @Rs.150.00 per sq m = 100*150 = Rs.150000.00

Net return:

On building @ 6% on the expense of development = 700000.00 *6/100 = Rs.42000.00

On the land @ 4% on the expense of land = 700000.00 *6/100 = Rs.6000.00

All out net lease each year = Rs.48000.00

Net lease = Net lease + outgoings = 48000+24000.00 = 72000.00 per annum

Net lease each month = 72000/12 = 6000.00.

27.The aggregate sum of sinking asset to be amassed toward the finish of 20 years.

S = 30000 * 90/100 = Rs.27000.00

Yearly portion of sinking store.

I = Si/[(1+i)n-1] = 27000*0.04/(1+0.04)20-1 = 27000*0.0336 = Rs.907.20

Yearly Portion for sinking store needed for a very long time = Rs.907.20.

28.The yearly sinking store, I = Si/[(1+i)n-1] = 2500*0.04/(1+0.04)15-1 = 2500*0.05 = Rs.125

The proprietor is to store Rs.125/ - yearly in 4% accruing funds conveying venture for a very long time to aggregate Rs.2500/ - .

29.For Rs.5.00 interest, capital Rs.1000.00

To get Rs.1000.00 interest, capital = (100/5)*1000

= Rs.20000.00

In short promoted esteem is - Net yearly income*Year's buy

For a similar overall gain if the pace of revenue is 8% the promoted esteem = 1000*(100/8) = Rs.12500.00.

30._____________ is the strategy of assessing or deciding the reasonable cost or estimation of a property like a structure, a manufacturing plant, other designing constructions of different kinds.

31.Year's buy = 100/6 = 16.67

Promoted estimation of the property = Total compensation * Y.P. = 900*16.67 = Rs.15003.00.

32.Average compensation = 400+1000/2 = Rs. 700.00 each month.

Normal month to month lease @ 10% of pay = 700.00/10 = Rs.70.00

Normal yearly lease 70.0*12 = Rs.840.00.

Capital expense of the structure @ 6%interest = 840*100/6 = Rs.14000.00

Plinth territory required @Rs.150.00 per sq m of plinth region = 14000/150 = 93.33 sq m.

Regularly the quarter for the associate architect ought to be built at the expense of Rs.14000.00 having plinth space of 93.33 sq m.

Yet, because of the expansion in the expense of development, this might be expanded by 100% and the capital expense of development might be fixed as Rs.2800.00 and the surmised plinth space of 93.33.

33.Set z = 0 in the condition, you get 0 = 4-y2. That streamlines to y2 = 4, or y = 2, for example two lines: y = 2 and y = - 2.

34.The articulation of the arithmetical increment strategy is given by PO+n*x, where PO is the current populace, x is the normal of the populace expansion in known decade and n is the quantity of many years.

35.The articulation of mathematical increment strategy is given by PO (1 + R/100) n

where PO is the current populace, R is the normal rate development rate each decade and n is the quantity of many years.

36.In the gradual increment technique, the populace for the following decade is found by adding to the current populace, the normal increment in addition to the normal steady increment each decade, henceforth joins both arithmetical and mathematical strategies.

37.The relative populace of particles in two states with energy E1 and E2 is given by

N2/N1 = e(E2E1)kT

E2 - E1 = hv

= hc/

= 1.79 eV

Accordingly, N2/N1 = e1.79kT

= e-69.3

= 8 X 10-31.