$(20$ points$)$ Suppose that $f$ is an odd function, $g$ is even, both are integrable on $-1,1,$ and we know that ${\displaystyle \underset{0}{\overset{1}{}}}f(x)dx=12,$ while ${\displaystyle \underset{0}{\overset{1}{}}}g(x)dx=4.$ If possible, find

${\displaystyle \underset{-1}{\overset{1}{}}}[3f(x)-2g(x)]dx$