Question: 2 . 1 1 EXAMPLE - FORCED VIBRATION - STEADY STATE A horizontal dynamic force P ( t ) = 5 0 s i n

2.11 EXAMPLE - FORCED VIBRATION - STEADY STATE
A horizontal dynamic force P(t)=50sin28t,(kN) is applied to joint A of the
portal frame shown below:
Given:
Size of the columns: 500mm500mm
Damping ratio: 5%
The girder supports a mass of 20 tones
Modulus of elasticity =30GPa
The beams (floor system) is rigid
(infinitely stiff).
The axial deformation in columns can be neglected and assume that the frame
remains in the elastic region.
Stiffness of the columns =12EIL3
usS(t)=(ust)osin(t-)(1-2)2+(2)2,;,=tan-1(21-2);=n
Rd=1(1-2)2+(2)2
Required:
Compute the lateral stiffness of each column
Compute the lateral stiffness of the frame
Compute the natural angular frequency
Compute the natural cyclic frequency
Compute the natural period
Compute the static deflection
Compute the frequency ratio ()-1
Find the dynamic response factor (Rd)
Find the steady state amplitude of the frame vibration
Develop the steady state equation of motion
Find the steady state displacement response at time t=1.5 seconds.
Plot the steady state response of the frame in the first 2 seconds
Compute the maximum dynamic base shear of the frame
2 . 1 1 EXAMPLE - FORCED VIBRATION - STEADY STATE

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