$2\mathrm{.}25$

Let $y=f(x)$ be the solution of the differential equation $f(0)=06{\displaystyle \underset{-\frac{1}{2}}{\overset{\frac{1}{2}}{}}}f(x)dx=2-{}^2\frac{dy}{(d)x}+\frac{xy}{x^2-1}=\frac{x^6+4x}{\sqrt[\phantom{2}]{1-x^2}},-1$ such that $f(0)=0.If6{\displaystyle \underset{-\frac{1}{2}}{\overset{\frac{1}{2}}{}}}f(x)dx=2-$ then ${}^{2}is$ equal $to$