$2.(25$ pts$)$ Use the sequence of random numbers given below and estimate:

i$)$ Average number of customers in the system

ii$)$ Average time spent in the queue

iii$)$ The average utilization of each server

iv$)$ Probability of no waiting in the queue

$($Use the following sequence of random numbers: $0\mathrm{.}4970\mathrm{.}3800\mathrm{.}8620\mathrm{.}0200\mathrm{.}3910\mathrm{.}975$

$0\mathrm{.}4800\mathrm{.}9050\mathrm{.}7590\mathrm{.}5600\mathrm{.}5930\mathrm{.}7440\mathrm{.}0690\mathrm{.}3700\mathrm{.}7900\mathrm{.}1760\mathrm{.}0200\mathrm{.}7140\mathrm{.}5390\mathrm{.}9280\mathrm{.}860$

$0\mathrm{.}7170\mathrm{.}8610\mathrm{.}5630\mathrm{.}5430\mathrm{.}8580\mathrm{.}5370\mathrm{.}2070\mathrm{.}5300\mathrm{.}7230\mathrm{.}9230\mathrm{.}1400\mathrm{.}6110\mathrm{.}2250\mathrm{.}3700\mathrm{.}603$

$0\mathrm{.}8700\mathrm{.}132).$

$($Use continuous time. When an arrival and a departure must be simultaneously scheduled,

use the convention of scheduling the arrival first$).$